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I have an XML file and I would like to replace everything that is between the open and closing tag within multiple instances of the g:gtin node with nothing.
Is this possible from the command line, using sed or something similar?
<g:gtin>31806831001</g:gtin>
A simple solution for simple cases - see my comment:
echo "<g:gtin>31806831001</g:gtin>" | sed 's|<g:gtin>.*</g:gtin>|<g:gtin></g:gtin>|'
Result:
<g:gtin></g:gtin>
It depends on the assumption that start and endtag are on the same line, and not more than one tag is on that line.
Since xml files are often generated the same way, over and over again, the assumption might hold.
<g:gtin>(.*?)</g:gtin> with <g:gtin></g:gtin> or something to that effect?
– crmpicco
Apr 20 '12 at 15:21
sed 'sedcommands' feed.xml would be your option. If you have multiple sed commands, you can put them into a file too: sed -f commands.sed feed.xml. There are many options. An -i flag: sed -i 'commands' feed.xml would change your file in place.
– user unknown
Apr 20 '12 at 15:36
sed specification. sed and regex are not the correct or most robust way to be handling XML anyways.
– jw013
Apr 20 '12 at 16:52
One way using perl:
Content of script.pl:
use warnings;
use strict;
use XML::Twig;
die qq[Usage: perl $0 <xml-file>\n] unless @ARGV == 1;
my $twig = XML::Twig->new(
twig_roots => {
q[g:gtin] => \&handle_gtin,
},
twig_print_outside_roots => 1,
);
$twig->parsefile( shift );
sub handle_gtin {
my ($t, $gtin) = @_;
$gtin->set_text( q[] );
$gtin->print;
}
Run it like:
perl script.pl file.xml
