I am trying to perform a mathematical operation with sed, but it continues to treat my variables as strings. The input is of this kind:

$echo 12 | sed 's/[0-9]*/&+3/'$ 12+3


I'd like to have 15 as output. I need to do the operation and replace its mathematical result in only one passage, because I am running the program as a Python daemon, and I want to avoid passages like redirecting stdout on files, open those files, perform operations, extract the result, do the replacement. To me, sed seems the best to perform all in one line.

I've tried to cast both input and output in various ways like

$echo 12 | sed 's/[0-9]*/int(&+3)/'$ echo 12 | sed 's/[0-9]*/\int(&+3)/'
$echo 12 | sed 's/[0-9]*/\int(&+3)/'  but the result was always a printing of the second field. • It's treating your "variables" as strings because that's all sed does - string manipulation. It has no concept of "integer." Apr 20 '12 at 16:10 • I'm very curious why you want to use sed to do math Apr 21 '12 at 13:43 • I just thought it could easily cast variables, didn't realize was so complex! Apr 22 '12 at 16:56 • I'm a little late, but vim users have maybe done math in a search and replace command before and since sed is very similar to vim search and replace, one would assume you could do the same type of stuff with it @DavidOneill Dec 27 '19 at 18:04 ## 12 Answers If you honestly want to use sed, then this is the way to go: s/[0-9]/<&/g s/0//g; s/1/|/g; s/2/||/g; s/3/|||/g; s/4/||||/g; s/5/|||||/g; s/6/||||||/g s/7/|||||||/g; s/8/||||||||/g; s/9/|||||||||/g : tens s/|</<||||||||||/g t tens s/<//g s/+//g : minus s/|-|/-/g t minus s/-$//
: back
s/||||||||||/</g
s/<$$[0-9]*$$$/<0\1/ s/|||||||||/9/; s/||||||||/8/; s/|||||||/7/; s/||||||/6/; s/|||||/5/; s/||||/4/ s/|||/3/; s/||/2/; s/|/1/ s/</|/g t back  Input: 1+2 100+250 100-250  Output: 3 350 -150  Your mission, should you choose to accept it, is to implement multiplication. • +1 for the challenge, love it! Maybe that'd be something for Code Golf ;-p Apr 20 '12 at 14:15 • And some people say that programming is not mathematics. This little gem refutes them all. Best use of Base 1 ever. Apr 20 '12 at 15:42 • Nice one! - @Simon: I challenge you to implement tetration :P – A T Apr 20 '12 at 17:45 • +1 This is a beautiful example of what a misconception paired with creativity can breed. Apr 20 '12 at 19:28 • Multiplication be done with sed - and it scales to huge numbers quite well, too! Apr 13 '16 at 20:07 sed isn't the best option here, it doesn't do arithmetics natively (see Increment a number for how you could possibly do it though). You could do that with awk: $ echo 12 | awk '{print $0+3}' 15  The best piece of code to use will depend on the exact format of your input and what you want/need to do if it is not numeric, or contains more than one number, etc. You could also do this only with bash: $ echo $(($(echo 12) + 3 ))


or using expr in a similar fashion.

I tried to accept your challenge @Richter, this is what I did using part of your code:

sed 's/[0-9]/<&/g
s/0//g; s/1/|/g; s/2/||/g; s/3/|||/g; s/4/||||/g; s/5/|||||/g; s/6/||||||/g
s/7/|||||||/g; s/8/||||||||/g; s/9/|||||||||/g
: tens
s/|</<||||||||||/g
t tens
s/<//g
s/.*\*$/0/ s/^\*.*/0/ s/*|/*/ : mult s/$$|*$$\*|/\1<\1*/ t mult s/*//g s/<//g : back s/||||||||||/</g s/<$$[0-9]*$$$/<0\1/
s/|||||||||/9/; s/||||||||/8/; s/|||||||/7/; s/||||||/6/; s/|||||/5/; s/||||/4/
s/|||/3/; s/||/2/; s/|/1/
s/</|/g
t back'


Input:

04*3
4*3
40*3
42*32
150*20
1*3
3*1
0*3
3*0


Output: all the correct results

perl allows for a very similar construct to sed's ... one difference is that perl can do more complex things... sed is very good for simple text substitions

 echo 'a12' | perl -pe 's/([0-9]+)/($1+3)/e' # the trailing /e means evaluate  output a15  • can also do this without the capturing parentheses: perl -pe 's/[0-9]+/$&+3/e' Apr 20 '12 at 13:12

just feed the string into a calculator

 echo 12 | sed 's/[0-9]*/&+3/' | bc

• this won't work if there's text amongst the numbers. Apr 21 '12 at 12:25

I really don't get why the extreme complexity of the accepted answer, either of the below do what you want:

echo 12 | sed 's/[0-9]*/echo \$(( & + 3 ))/e'  or echo 12 | sed 's/[0-9]*/expr & + 3/e'  I think it might require GNU sed, but I am not sure. • It is a gnu extension. Mar 30 '13 at 17:02 • Ok you are right but the answer goes beyond, it implements the general addition not a particular one, you can feed any two numbers and you will get the result Apr 1 '13 at 18:56 • @LuigiTiburzi Its fairly straightforward to generalize this to "x+y" style input: echo 12+3 | sed -r 's/([0-9]*) *\+ *([0-9]*)/expr \1 + \2/e' Oct 15 '14 at 18:28 If you definitely have to combine regular expressions and arithmetic operations, choose a language where the regular expression's replacement parameter can be a callback function. Perl, Ruby, JavaScript and Python are such languages: bash-4.2$ echo 12 | perl -pe 's/\d+/$&+3/e' 15 bash-4.2$ echo 12 | ruby -pe '$_.sub!(/\d+/){|s|s.to_i+3}' 15 bash-4.2$ echo 12 | js -e 'print(readline().replace(/\d+/,function(s){return parseInt(s)+3}))'
15

bash-4.2$echo 12 | python -c 'import re;print re.sub("\d+",lambda s:str(int(s.group(0))+3),raw_input())' 15  Another simple bash solution, that actually works in a pipe:  echo 12 | { read num; echo$(( num + 3)); }


If you mix in some bashism:

echo $(($(echo 12 | sed 's/[0-9]*/&+3/')))


To extract the number from a text:

echo $(($(echo "foo12bar" | sed -r 's/[^0-9]*([0-9]*).*/\1+3/')))


Without sed, just bash:

var="foo12bar"
echo $((${var//[^0-9]/}+3))


replaces every non-digit ${var//[^0-9]/} and does arithmetic in double round parens: $((x+3))

• There's no bashism in there. $((...)) was introduce by POSIX (the bashism is $[...]). ${var//xxx/x} is a kshism also copied by zsh and bash. sed -r is a GNUism Sep 18 '12 at 22:06 Here's a Perl solution: echo 12 | perl -wlpe '$_ += 3'
# Output:  15


If you prefer to change the first set of digits encountered in a string, you can use:

echo I am 12 years old. | perl -wlpe 's/(\d+)/$1 + 3/e' # Output: I am 15 years old.  If you prefer to change all the sets of digits in a string, you can use the /g modifier, like this: echo They are 11, 12, and 13 years old. | perl -wlpe 's/(\d+)/$1 + 3/eg'
# Output:  They are 14, 15, and 16 years old.


Although using sed expression is great it has its limitations. For example following fails:

$echo "1000000000000000000000000000000+1" | sed -e 's/$$[0-9]*$$+$$[0-9]*$$/expr \1 + \2/e' expr: 1000000000000000000000000000000: Numerical result out of range  To overcome this limitation one my simply turn to the built in power of pure sed and implement following arbitrary length decimal adder: #!/bin/sed -f s/+/\n/g s/$/\n\n0/

:LOOP
s/^$$.*$$$$.$$\n$$.*$$$$.$$\n$$.*$$\n$$.$$$/0\1\n0\3\n\5\n\6\2\4/ h s/^.*\n.*\n.*\n$$...$$$/\1/

# INPUT:  3digits (Carry in, A, B,)
# OUTPUT: 2bits (Carry, Sum)
s/$/;000=00001=01002=02003=03004=04005=05006=06007=07008=08009=09010=01011=02012=03013=04014=05015=06016=07017=08018=09019=10020=02021=03022=04023=05024=06025=07026=08027=09028=10029=11030=03031=04032=05033=06034=07035=08036=09037=10038=11039=12040=04041=05042=06043=07044=08045=09046=10047=11048=12049=13050=05051=06052=07053=08054=09055=10056=11057=12058=13059=14060=06061=07062=08063=09064=10065=11066=12067=13068=14069=15070=07071=08072=09073=10074=11075=12076=13077=14078=15079=16080=08081=09082=10083=11084=12085=13086=14087=15088=16089=17090=09091=10092=11093=12094=13095=14096=15097=16098=17099=18100=01101=02102=03103=04104=05105=06106=07107=08108=09109=10110=02111=03112=04113=05114=06115=07116=08117=09118=10119=11120=03121=04122=05123=06124=07125=08126=09127=10128=11129=12130=04131=05132=06133=07134=08135=09136=10137=11138=12139=13140=05141=06142=07143=08144=09145=10146=11147=12148=13149=14150=06151=07152=08153=09154=10155=11156=12157=13158=14159=15160=07161=08162=09163=10164=11165=12166=13167=14168=15169=16170=08171=09172=10173=11174=12175=13176=14177=15178=16179=17180=09181=10182=11183=12184=13185=14186=15187=16188=17189=18190=10191=11192=12193=13194=14195=15196=16197=17198=18199=19/ s/^$$...$$[^;]*;[^;]*\1=$$..$$.*/\2/ H g s/^$$.*$$\n$$.*$$\n$$.*$$\n...\n$$.$$$$.$$$/\1\n\2\n\5\3\n\4/
/^$$[0]*$$\n$$[0]*$$\n/ {
s/^.*\n.*\n$$.*$$\n$$.$$/\2\1/
s/^0$$.*$$/\1/
q
}
b LOOP


The way it works is by implementing decimal adder module that adds two input digits (A and B) as well as Carry Bit and produces a Sum and Carry bit. The idea is borrowed from electronic where binary adder does the same for binary numbers. All we have to do is loop the adder over all digits and we can add arbitrary length numbers (limited by memory). Below is the adder in action:

./decAdder.sed
666666666666666666666666666666999999999999991111111112222+1100000000000000000000011111111111111111111111111111111111
1766666666666666666666677777778111111111111102222222223333


In exactly the same way one can implement binary (or any other base) adder. All you have to do is replace the line that starts with s/$/;000=00001... with proper substitution pattern for given base. For example: s/$/;000=00001=01010=01011=10100=01101=10110=10111=11/ is substitution pattern for arbitrary length binary adder.

You can fit the code documented on my github.

Not sure if the 'e' flag for the 's' command has been discussed yet but here's how I'd solve this problem

$echo 12 | sed -E 's/[0-9]*/expr & + 3/e' 15  the 'e' flag takes the current pattern line and runs it as a command before replacing the pattern space with the output. In this case using the 'expr' command to do our math. source: The S Command A little more complicated, but converts multiple digits that end in a space from bytes->kilobytes (avoids numbers with a percent sign) $ df | sed -E '1!{s/(\b)([0-9]+)(\s)/\1$(expr \2 \/ 1024)kb\3/g};s/.*/printf "%s" "&"/e' Filesystem 512-blocks Used Available Capacity iused ifree %iused Mounted on /dev/disk1s5 478144kb 21563kb 141089kb 14% 477kb 2390246kb 0% / devfs 0kb 0kb 0kb 100% 0kb 0kb 100% /dev /dev/disk1s1 478144kb 297544kb 141089kb 68% 1727kb 2388995kb 0% /System/Volumes/Data /dev/disk1s4 478144kb 16384kb 141089kb 11% 0kb 2390723kb 0% /private/var/vm map auto_home 0kb 0kb 0kb 100% 0kb 0kb 100% /System/Volumes/Data/home /dev/disk2s1 1188kb 987kb 201kb 84% 0kb 4194303kb 0% /Volumes/RecoveryHDMeta /dev/disk3s1 3822kb 2528kb 1294kb 67% 46kb 4194257kb 0% /Volumes/macOS Base System  1. wraps each number in '$(' & ')' the '1!{' & '}' makes sure that this ignores the first line
1!{s/(\b)([0-9]+)(\s)/\1\$(expr \2 \/ 1024)kb\3/g};

1. matches whole line & prefixes line with the printf command, the e flag will then execute each line
;s/.*/printf "%s" "&"/e'