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sed -n -E -e '/word/,$ p' filename.txt

More specific Questions:

Why is -e needed here? Does it serve any purpose in the example?

I know p is for print and $ indicates the end of the line but what does the compination ,$ p do exactly here?

  • In the context of an address range, $ means the last line of the file rather than the end of a line: see Addresses overview – steeldriver May 13 '17 at 16:50
  • I might recommend to have at hand any of the cheatsheets that can be found in the web. This URL searches for PDF's of them on Duckduckgo – XavierStuvw May 13 '17 at 17:46
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/word/,$ is the address range for the p command.

/word/,$p will apply the p command (print) to all lines from the first that contains word anywhere on it, to the end of the file.

-e is not needed in this example as there is only one expression for sed to execute. You also do not need -E as the example is not making use of POSIX extended regular expressions.

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  • -e tell sed to use next arg as command
  • /word/,$ select all line from the one having word to end of file.
  • p print

if you forget -n you will have whole file printed

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