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I have a json file with a line as below,

"image": "docker.abc.com/abc-pr0000abc:ABCCoreUI-46",

Can some one help me with sed command that can replace above as below,

"image": "docker.abc.com/abc-pr0000abc:ABCCoreUI-47",

Also I would like to wild card 46, something like ABCCoreUI-*

I tried sed s/ABCCoreUI-4*/ABCCoreUI-47/ file.json

Output become,

"image": "docker.abc.com/abc-pr0000abc:ABCCoreUI-4742",

Thanks

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  • Are the xxxs static obfuscated strings, or are they different in every instance you wish to alter?
    – DopeGhoti
    Commented May 9, 2017 at 16:54
  • thats correct. xxx is always static.
    – Simon
    Commented May 9, 2017 at 17:00
  • in regex (used by sed) * means any 0 or more of previous atom (character or bracketed thing). You are mixing it up with globs. Just replacing your * with .* should do it. ( . means any character [.] or \. means . ).
    – ctrl-alt-delor
    Commented May 9, 2017 at 18:07

4 Answers 4

Reset to default
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Also I would like to wild card 46, something like ABCCoreUI-*

I think no one answered what you asked "FIX your pattern to match any digit at the end of your string, maybe due to behavior of * character at last position, output is concatenating 47+42"

You may wrap the regexp in '' to prevent Shell Globs

Then, to match zero or more digits

sed -r 's/ABCCoreUI-[0-9]*/ABCCoreUI-47/' file.json
sed -r 's/ABCCoreUI-[[:digit:]]*/ABCCoreUI-47/' file.json

To match zero or more characters

sed -r 's/ABCCoreUI-.*/ABCCoreUI-47/' file.json
  • -r is to enable extended sed regexp
  • [0-9] or [[:digit:]] (POSIX) to match a digit
  • [0-9]* or [[:digit:]]* to match zero or more digits
  • .* to match zero or more characters

Note that \d is not working.

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  • + requires extended regular expressions. You'd need an option like -E for that. And \d is unknown to most sed implementations; use [0-9] instead.
    – Philippos
    Commented May 10, 2017 at 10:49
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This quick-and-dirty sed appears to do the trick:

sed '/image.*docker\.xxx\.com.*CoreUI-46/s/CoreUI-46/CoreUI-47/' /path/to/yourfile.json
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  • The OP not only wants to replace 46, but any number [0-9]*
    – Philippos
    Commented May 10, 2017 at 10:51
  • This was not made clear in the version of the question which I answered. Better answers have been provided in the interim since the clarification.
    – DopeGhoti
    Commented May 10, 2017 at 15:58
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In most simple case you can apply the following sed approach:

sed 's/\("image": "[^"]*-\)46"/\147"/g' jsonfile
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Below worked for me

sed "s|\(^.*\"image\": \"docker.abc.com/abc-pr0000abc:\).*|\ABCCoreUI-47\",|g" -i artifactorytest.json

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  • (1) I guess you forgot \1 in the replacement string. (2) ^ is not neccessary if you start with .*. (3) If you use single quotes for the script, you don't need to escape all double quotes. (4) We don't know whether the can be matches with other strings than `ABCCoreUI' that should be left alone.
    – Philippos
    Commented May 10, 2017 at 10:58

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