I use the command:

tr '\n' ' ' < input.txt > output.txt

to convert new lines to spaces using tr command.

It works fine for single files - but I have multiple files I need to run a single command on... similar to the following command for doing text swapping:

find /directory/. -type f -exec sed -i 's/oldtext/newtext/g' {} \;

Is there a command I can add to a bash script (like the one above using find) to remove \n?


This will work even without any loop for all filenames starting with file:

perl -pe 's/\n/ /g' file*

For such operations, i prefer perl. Has the same syntax with sed , is portable and don't have all those strange sed parameters. You can also apply -i switch to perl (like sed) to make in-place changes: perl -i.old -pe .... (old file will be backed up with extension .old -You can just use -i and no backup file will be kept)

If you prefer you can use your find command like this:

$ find . -type f -name 'file*' -exec bash -c 'tr "\n" " " <$0 >$0.new' {} \;
  • The /g modifier is redundant as there can be only one newline in a line. – user218374 May 1 '17 at 2:58
  • You need to redirect the output coming from tr back into the input filename for as it stands now, it's all flowing to the terminal. – user218374 May 1 '17 at 3:00
  • @speld_rwong Updated – George Vasiliou May 1 '17 at 11:01
perl -i -lpe '$\=$"' file.data

  • -i turns ON in-place editing.
  • -l sets ORS = RS = "\n"
  • -p sets up an implicit input file read in + automatic print of records.
  • $\ is the ORS which is set to $" = OFS = space by default.
  • Of course you can give multiple filenames to the perl command.

This is the sed command you are looking for:

find /directory/. -type f -exec sed -i ':begin;$!N;s/\n/ /;tbegin' {} \;

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