2

I would like to run the command find . '! -name *.*' in the bash shell. It does not work as intended. (It should list all files in the current directory for which -name *.* is false, i.e. which do not have a dot in their names.) Instead, it prints a list of all files in the directory and, paradoxically, ends with the line find: "! -name *.*": file or directory not found. I suspect the problem is interpretation of the expression by the shell, although it is protected by the two apostrophe (U+0027) characters. Are there ways to protect the expression reliably whatever the expression is?

I use this version: find (GNU findutils) 4.4.2

5

Due to the OP quoting the expr '! -name *.*' it turns into the 2nd argument to find. So now what find thinks is that you passed to it 2 directory names, viz., . and a crazy name ! -name *.*, so it'll faithfully try to list out all files/subdirs recursively in these two. With . so far so good, but when the time comes to dive into that crazy dir. ! -name *.* it can't, unless you have it. And even then, find won't be doing what you wanted.

For that you have to quote at the proper places:

find . ! -name '*.*'

or

eval find . '! -name "*.*"'
1

Try putting the single quotes around the expression only.

find . ! -name '*.*'

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