This is my homework to write calculator on shell script but there is two errors and I couldn't find the solutions.

echo "---------Welcome to Simple Calculator--------"
echo "p=PLUS"
echo "m=MINUS"
echo "d=DIVISION"
read -p "Enter your choice" ch
if $ch -eq p
    echo "Enter Two Number For PLUS"
    read x
    read y
    echo "Sonuç:  $((x+y))"
elif $ch -eq m
    echo "Enter Two Number For MINUS"
    read x
    read y
    echo "Sonuç: $((x-y))
elif $ch -eq x
    echo "Enter Two Number For  MULTIPLICATION"
    read x
    read y
    echo "Sonuç: $((x\*y))"
elif $ch -eq d
    echo "Enter Two Number For DIVISION"
    read x
    read y
    echo "scale=2;x/y" | bc
    echo "Stopping calculator"
  • The second "Sonuç: $((x*y)) is missing the closing parentheses. – Mike Waters Mar 13 '17 at 17:42
  • Nope. It is missing a double quote, but the parenthesis are fine – Bruno9779 Mar 13 '17 at 17:45
  • Generally it's helpful to include the error messages you get, or to provide a worked example that triggers the errors. – roaima Mar 13 '17 at 17:58

Using a shell syntax checker such as https://www.shellcheck.net/ will help you identify the more obvious syntax errors, such as missing quotes.

However, it won't help with your if ... then clauses, all of which are missing a test operator. Here's an example:

if $ch -eq p

This will fail with some sort of "Command not found" error when you try to run it. (This is why it's helpful to include the output from running a program in the question.)

What you probably meant was this, which uses the test operator [[..]] to perform a string comparison rather than a numeric one.

if [[ "$ch" == p ]]

Finally, it's good practice to double-quote all your variables everywhere you use them, i.e. "$ch" instead of $ch.

  • 1
    Additionally -eq performs an equality test on two integers... It would be better to us a case statement here. – Kusalananda Mar 13 '17 at 18:08
  • @Kusalananda thanks. Case statement? Yes agreed but I assumed the OP hadn't got that far through Scripting 101 yet. – roaima Mar 13 '17 at 18:09

In the subtraction section you are missing a " (double quote):

echo "Sonuç: $((x-y))

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