I am trying to collect lines from a file with the specific word host: for example the word host, I need to get output of all names of hosts. This is my file:

host= mx,rt,fd,rt,wed,asd, \
      fm, jklf,dfd,dfd
host = jd,er,ew,yu,tg,ed,ik,cs,\
       fd, gr, jy
host = mz,fg,jh

I am using :

$grep -i host filename | awk '{print $2}'

only works for the first line , it does not output any name after \

so the output is;

   mx,rt,fd,rt,wed,asd, \



as you see I am not getting rest of the line after \

I don't want to get rid of \ I would like to keep it, I can move it and connect all names, so it will be seen as one_line , but I don't want to do that.

Any idea , it is appreciated, it could be easy , but I can make it work, even when I use tr.

  • 3
    Show what your input is and what output you want. The fact that nobody responds is that you should rephrase your question. Feb 27, 2017 at 20:45

2 Answers 2


You could do:

 sed '
   # delete all but lines starting with host= (allowing blanks)

   # remove that host= part
     # if the line ends in \, append the next line and loop 

Give this a shot awk '{gsub("host","");gsub("=","");print;}' filename

awk remove the host and = and then just print each line.

  • It's standard awk (awk '{print;}'). Just try it. I already did. Feb 27, 2017 at 21:38
  • awk '{gsub("host","");gsub("=","");print;}' filename____ this Worked Thank you, it is very appreciated
    – Moez
    Feb 27, 2017 at 22:28

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