-1
zgrep -f /onip/appt/app/yemi/usage_biglist.txt \
    /onip/cdr/output/nor/bac/filec/$count/nordat.gz \
    >> /onip/appt/app/yemi/have_usage.txt

Summary

  1. pick the first string in file usage_biglist.txt
  2. grep it from file nordat.gz and save the result to have_usage.txt
  3. pick next string in usage_biglist.txt and do the same till nth string
1

grep (or zgrep in your case) will always output all matching lines from a file.

You could do each pattern match individually, and pass the result through head -n 1 though:

while read -r pattern; do
    zgrep "$pattern" file.gz | head -n 1
done <pattern_list.txt >output_file.txt

In your case:

while read -r pattern; do
    zgrep "$pattern" /onip/cdr/output/nor/bac/filec/$count/nordat.gz | head -n 1
done </onip/appt/app/yemi/usage_biglist.txt >/onip/appt/app/yemi/have_usage.txt
1

Use

zgrep -m 1 -f

in the place of

zgrep -f
  • 1
    As far as I am aware this is a feature of GNU grep only. It is worth to mention it. – Kalavan Jan 31 '17 at 13:11
  • 1
    @Kalavan - even if OP was using gnu grep this doesn't do what they want i.e. print first match for each string in the list – don_crissti Jan 31 '17 at 13:15
  • @don_crissti, You are right! I focused on a sub-problem and stopped there :/ – Kalavan Jan 31 '17 at 13:17
1

I'd use awk:

gunzip < "/onip/cdr/output/nor/bac/filec/$count/nordat.gz" |
  awk '
    !list_processed {strings[$0]; next}
    {
      do_print = 0
      for (s in strings)
        if (index($0, s)) {
          delete strings[s]
          do_print = 1
        }
    }
    do_print
  ' /onip/appt/app/yemi/usage_biglist.txt list_processed=1 - \
    >> /onip/appt/app/yemi/have_usage.txt

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