How to print a specific column condition using awk?

Question

I have an input file :

A 123 name: 1 AAA  
B 123 name: 2 AAA name: 3 BBB  
C 234 name: 1 AAA name: 2 BBB name: 5 CCC 

If the column is 'name:', I want to print the next and the next column.

This is my awk code:

cat input.txt | awk '{for(i=1;i<=NF;i++)if($i == "name:")print $(i+1),$(i+2)}'

But, in this case, all columns are listed in a line like this:

1 AAA  
2 AAA  
3 BBB  
1 AAA  
2 BBB  
5 CCC

I want the columns to be printed like this:

1 AAA  
2 AAA 3 BBB    
1 AAA 2 BBB 5 CCC

Answer 1

Just replace print with printf to print the value on the same line, and insert new line after finishing the iteration on the the line:

awk '{{for(i=1;i<=NF;i++)if($i == "name:") printf $(i+1)" "$(i+2)" "} print ""; }' yourfile

The output:

1 AAA 
2 AAA 3 BBB 
1 AAA 2 BBB 5 CCC