Excluding a file in bash loop

Question

In the following script, How do I exclude a directory in the loop? I want to do this because all files are symlinks pointing to this directory that exists in the same level, so I don't want to add it.

cd /var/www
for dir in */
do
        base=$(basename "$dir")
        tar -czfh "${base}.tar.gz" "$dir"
done

Answer 1

You can add a continue statement like this :

cd /var/www
for dir in */
do
        if [ "$dir" == "foo" ] ; then
              continue;
        fi
        base=$(basename "$dir")
        tar -czfh "${base}.tar.gz" "$dir"
done

Or you can do it with find command :

find /var/www -maxdepth 1 -type d \( -name foo \) -prune -o -print -exec bash -c "tar -czfh \`basename {}\`.tar.gz {}" \;

Answer 2

You need to enable extglob for this if it's not already enabled (shopt -s extglob):

for dir in !(dirname)/
...