0
egrep -i '12-12.*\swarning' log.file | cless

The above will produce two lines with the date 12-12, followed by random characters, a white space, then Warning and more text.

2011-12-12 textetc Warning 1234
2011-12-12 textetc Warning 5678

I wish it only to return lines that DO NOT contain 1234 at the end. I'm using GNU grep 2.5.4.

Currently, this is my workaround.

egrep -i '12-12.*\swarning' log.file > tmp.txt
egrep -i -v '1234' tmp.txt

I've tried piping the first to the second (without creating a file), but it either returns way too much, and it's all wrong, or it returns nothing at all.

2

You have to use 2 greps.

grep -i '12-12.*[[:space:]]warning' log.file | grep -v '1234$'

Alternatively, you could use one awk

awk '/12-12.*[[:space:]]warning/ && ! /1234$/' log.file
1
  • Thanks! You solved my issue with the first line. My problem was that I thought I had to add the file I was grepping in the second statement.
    – r.misc
    Feb 17 '12 at 22:49

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.