I know how to mount a drive that has a corresponding device file in /dev, but I don't know how to do this for a disk image that does not represent a physical device and does not have an analogue in /dev (e.g. an ISO file or a floppy image). I know I can do this in Mac OS X by double-clicking on the disk image's icon in Finder, which will mount the drive automatically, but I would like to be able to do this from the terminal. I'm not sure if there is a general Unix way of doing this, or if this is platform-specific.
4 Answers
If it was a hard-drive image with a MBR partition table, I would fdisk the image to find the offset for the partition I need to mount.
fdisk -lu /path/disk.img
Then I would mount it passing the offset.
mount -o loop,offset=xxxx /path/disk.img /mnt/disk.img.partition
The offset value is in bytes, whereas fdisk
shows a block count, so you should multiply the value from the "Begin" or "Start" column of the fdisk
output by 512
(or whatever the block size is) to obtain the offset to mount at.
-
15
losetup -P
is generally more convenient than this method: unix.stackexchange.com/a/316407/32558 Commented Mar 15, 2018 at 15:11 -
1+1 This is the solution that worked for me. Thank you for including details on how to calculate the offset as well.– ali14Commented Apr 18, 2022 at 13:04
On most modern GNU system the mount
command can handle that:
mount -o loop file.iso /mnt/dir
to unmount you can just use the umount
command
umount /mnt/dir
If your OS doesn't have this option you can create a loop device:
losetup -f # this will print the first available loop device ex:/dev/loop0
losetup /dev/loop0 /path/file.iso #associate loop0 with the specified file
mount /dev/loop0 /mnt/dir #It may be necessary specify the type (-t iso9660)
to umount you can use -d
:
umount /mnt/dir
losetup -d /dev/loop0
If the file have partitions, example a HD image, you can use the -P
parameter (depending on you OS), it will map the partitions in the file content:
losetup -P /dev/loop0 /path/file.iso # will create /dev/loop0
ls /dev/loop0p* #the partitions in the format /dev/loop0pX
-
This is basically
localhost
(loopback!) for disk images. Commented Oct 14, 2016 at 16:17 -
3
losetup
andmount -o loop
are Linux specific. It won't work on GNU distributions using a different kernel (like hurd, illumos or kFreeBSD though illumos and FreeBSD will have the equivalent with a different syntax) Commented Oct 14, 2016 at 22:07 -
Here are some functions to further automate
losetup
: unix.stackexchange.com/a/430415/32558 Commented Mar 15, 2018 at 15:11 -
1I don't understand the meaning of a "loop device" nor why you need
-o loop
to mount the image file as one. Can you explain please? I see the Wikipedia link but still don't understand. I have an embedded Linuxrootfs.ext2
roof filesystem image, and it doesn't seem to make any difference when I mount it with vs without-o loop
to inspect the files. Commented Aug 11, 2022 at 1:29
losetup -P
automation for multi partition images
How to mount a disk image from the command line? | Unix & Linux Stack Exchange mentioned losetup -P
, and here are some handy Bash functions to further automate things. Usage:
$ los my.img
/dev/loop0
/mnt/loop0p1
/mnt/loop0p2
$ ls /mnt/loop0p1
/whatever
/files
/youhave
/there
$ sudo losetup -l
NAME SIZELIMIT OFFSET AUTOCLEAR RO BACK-FILE DIO
/dev/loop1 0 0 0 0 /full/path/to/my.img
$ # Cleanup.
$ losd 0
$ ls /mnt/loop0p1
$ ls /dev | grep loop0
loop0
Source:
los() (
img="$1"
dev="$(sudo losetup --show -f -P "$img")"
echo "$dev"
for part in "$dev"?*; do
if [ "$part" = "${dev}p*" ]; then
part="${dev}"
fi
dst="/mnt/$(basename "$part")"
echo "$dst"
sudo mkdir -p "$dst"
sudo mount "$part" "$dst"
done
)
losd() (
dev="/dev/loop$1"
for part in "$dev"?*; do
if [ "$part" = "${dev}p*" ]; then
part="${dev}"
fi
dst="/mnt/$(basename "$part")"
sudo umount "$dst"
done
sudo losetup -d "$dev"
)
Try:
mount -o loop /path/to/file.iso /mnt
You might add, after loop
:
-t msdos
for floppy-t iso9660
for CD-ROM image
Linux usually tries to guess the file type.