How to delete the line after a search pattern, globally with vi?

Question

Assume I have a big file, ~1k lines, and I need to delete the line after some pattern, lets call it: somePatern.

Conditions:

• cannot be done by hand (no searching -- /somePattern, and/or manually moving down one line and deleting).
• preferably a single liner.
• line after the line that contains the pattern has to be gone (no empty line)
• has to be UNIX compatible (I use Debian but need it for UNIX -- great if works on both)

Also if anyone has a link to a site where I can learn this and more regex stuff that be awesome! (But not a beginners type of tut, I have that down, courtesy of vimtutor and others.)

Answer 1

g/somepattern/+d

In the following example baz was removed. (I only verified with Vim though.)

foo     
bar 
somepattern 
baz 
someotherpattern

Answer 2

Take a look here in section 3.2 "Range of Operation, Line Addressing and Marks". It seems that Vim commands can accept a line range in front of them. By specifying the line range you restrict the command execution to this particular part of text only.

For example:

/pattern[/] the next line where text "pattern" matches

?pattern[?] the previous line where text "pattern" matches