How to use sed to print part of a string containing hashes (or any alternative solution)?

Question

I am trying to print out a specific string within a line with sed.

The first problem is that I have some difficulties finding a string which contains slashes, I already tried some solutions provided in other threads but was unsuccessful, hopefully someone can help me.

I have a file called output.log.

An example of a line is:

013-11-08 19:45:52 evtlog.bad PROD/INSE/6004113 2012-11-08 19:04:06 /test11/golf/TierTwo/2013-11/evtlog.log

So with sed I want to print out only below string from this line:

/test11/golf/TierTwo/2013-11/evtlog.log

And I want to find the string in this line with: "golf/TierTwo/2013-11"

So I would use for example:

sed 'golf/TierTwo/2013-11' output.log

And get an output of:

/test11/golf/TierTwo/2013-11/evtlog.log

How can I achieve this?

If there would be a better solution instead of sed, it would be welcome also. My goal is to use this in a script, either bash or perl

Answer 1

Use awk instead of sed:

awk 'index($0,"golf/TierTwo/2013-11")>0 { print $7 }' output.log

this will search the string in each line, if an index is found 7th word will be printed.

Answer 2

If your grep supports the -o or --only-matching flag, you could grep for the string, surrounded by any contiguous non-whitespace characters

grep -o '[^[:blank:]]*golf/TierTwo/2013-11[^[:blank:]]*' output.log
/test11/golf/TierTwo/2013-11/evtlog.log

or (if it supports the perl-style \S class)

grep -Eo '\S*golf/TierTwo/2013-11\S*' output.log
/test11/golf/TierTwo/2013-11/evtlog.log

Answer 3

perl -naE 'say $F[6] if m!golf/TierTwo/2013-11!' logfile

perl -nae makes perl behave in a awk way...