Process manipulation

Question

$ps -fu $USER
UID        PID  PPID  C STIME TTY          TIME CMD
kanoujip 22471 21858  0 Sep16 pts/3    00:00:00 /bin/sh ./Alert_notification.sh
kanoujip 27450 27390  0 Sep16 ?        00:00:00 sshd: kanoujip@pts/9

I want to run another time ./Alert_notification.sh again so want to kill all previous runs from my User ID

How can I achieve this ?

ps -fu $USER | grep Alert_notification.sh |grep -vE 'grep|"$PPID"' | awk '{print $2}' | xargs kill `ps -o pid= -N T` ;

terminates all the MY USER session

Answer 1

If I understand well your request, you don't have to grep on the $PPID variable, that is used, maybe, even by your last called script execution, but on the PID of the last called script: $$.

If you call script.sh using the same bash, $PPID willi be the same for all the others execution of the script script.sh (or Alert_notifications.sh in your case).

Try changing something into your command and adding a little of control (if you want):

ps -fu $USER | grep  "Alert_notification.sh" | grep -v "grep\|$$" | awk '{print $2}' | xargs kill 2> /dev/null  

• 2> /dev/null: you need it to omit error messages in the case some it will be found no process