Print multiple search pattern in one line + text manipulation

Question

My output looks like this:

 /map1/firmware1   Targets   Properties
     version=2.44
     date=Jul 19 2016
     name=iLO 4

My desired output is:

version=2.44 date=Jul_19_2016

To merge the output into one line I tried to use xargs. But then he only prints date.

cat test | egrep '(version=|date=)' |xargs
 date=Jul 19 2016

Answer 1

OP's issue seems to be due to dos style line endings...

Example:

$ cat -e chk 
 /map1/firmware1   Targets   Properties^M$
     version=2.44^M$
     date=Jul 19 2016^M$
     name=iLO 4^M$

$ egrep '(version=|date=)' chk | xargs
 date=Jul 19 2016

After converting to unix style line ending:

$ perl -i -pe 's|\r\n|\n|' chk 

$ cat -e chk 
 /map1/firmware1   Targets   Properties$
     version=2.44$
     date=Jul 19 2016$
     name=iLO 4$

$ egrep '(version=|date=)' chk | xargs
version=2.44 date=Jul 19 2016

Answer 2

using sed one-liner

$ sed -n '/version/ {N; s/[\r\n]//g; p}' filename
     version=2.44     date=Jul 19 2016

Explanation

• /version/ matches pattern and executes the brace block { }.
• N takes next line from input file and appends it to pattern space.
• s/[\r\n]//g removes all newlines and carriage returns from pattern space.
• p prints pattern space.