My output looks like this:

 /map1/firmware1   Targets   Properties
     date=Jul 19 2016
     name=iLO 4

My desired output is:

version=2.44 date=Jul_19_2016

To merge the output into one line I tried to use xargs. But then he only prints date.

cat test | egrep '(version=|date=)' |xargs
 date=Jul 19 2016

OP's issue seems to be due to dos style line endings...


$ cat -e chk 
 /map1/firmware1   Targets   Properties^M$
     date=Jul 19 2016^M$
     name=iLO 4^M$

$ egrep '(version=|date=)' chk | xargs
 date=Jul 19 2016

After converting to unix style line ending:

$ perl -i -pe 's|\r\n|\n|' chk 

$ cat -e chk 
 /map1/firmware1   Targets   Properties$
     date=Jul 19 2016$
     name=iLO 4$

$ egrep '(version=|date=)' chk | xargs
version=2.44 date=Jul 19 2016
| improve this answer | |
  • paste leads also to the missing version egrep '(version=|date=)' test |paste - - date=Jul 19 2016 – M.S. Sep 16 '16 at 7:54
  • what is the output of file test ? does it have CRLF line terminators? – Sundeep Sep 16 '16 at 7:58
  • file test test: ascii text But I think you are right and there are diffrent line terminators. The output comes directly from an HP ILO – M.S. Sep 16 '16 at 8:02

using sed one-liner

$ sed -n '/version/ {N; s/[\r\n]//g; p}' filename
     version=2.44     date=Jul 19 2016


  • /version/ matches pattern and executes the brace block { }.
  • N takes next line from input file and appends it to pattern space.
  • s/[\r\n]//g removes all newlines and carriage returns from pattern space.
  • p prints pattern space.
| improve this answer | |
  • This works "half" :) I think that the output format will be the same over multiple servers, so I guess its okay to use "print next line after match". But I still want to swap the spaces in "date=Jul 19 2016" with _ – M.S. Sep 16 '16 at 7:58

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