63

I'm having trouble with escaping characters in bash. I'd like to escape single and double quotes while running a command under a different user. For the purposes of this question let's say I want to echo the following on the screen:

'single quote phrase' "double quote phrase"

How can I escape all the special chars, if I also need to switch to a different user:

sudo su USER -c "echo \"'single quote phrase' \"double quote phrase\"\""

Of course, this doesn't produce the right result.

  • +1 for "Of course, this doesn't produce the right results". bash is well on the way to making me mad. – Rolf Mar 30 '18 at 11:59
82

You can use the following string literal syntax:

> echo $'\'single quote phrase\' "double quote phrase"'
'single quote phrase' "double quote phrase"

From man bash

Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard. Backslash escape sequences, if present, are decoded as follows:

          \a     alert (bell)
          \b     backspace
          \e
          \E     an escape character
          \f     form feed
          \n     new line
          \r     carriage return
          \t     horizontal tab
          \v     vertical tab
          \\     backslash
          \'     single quote
          \"     double quote
          \nnn   the eight-bit character whose value is the octal value nnn (one to three digits)
          \xHH   the eight-bit character whose value is the hexadecimal value HH (one or two hex digits)
          \cx    a control-x character
12

In a POSIX shell, assuming in your string there is no variable, command or history expansion, and there is no newline, follow these basic prescriptions:

  1. To quote a generic string with single quotes, perform the following actions:

    1. Substitute any sequence of non-single-quote characters with the same sequence with added leading and trailing single quotes: 'aaa' ==> ''aaa''

    2. Escape with a backslash every preexisting single quote character: ' ==> \'
      In particular, ''aaa'' ==> \''aaa'\'

  2. To quote a generic string with double quotes, perform the following actions:

    1. Add leading and trailing double quotes: aaa ==> "aaa"

    2. Escape with a backslash every double quote character and every backslash character: " ==> \", \ ==> \\

A couple of examples:

''aaa""bbb''ccc\\ddd''  ==>  \'\''aaa""bbb'\'\''ccc\\ddd'\'\'
                        ==>  "''aaa\"\"bbb''ccc\\\\ddd''"

so that you example could be expanded with the following:

#!/bin/sh

echo \''aaa'\'' "bbb"'
echo "'aaa' \"bbb\""

sudo su enzotib -c 'echo \'\'\''aaa'\''\'\'\'' "bbb"'\'
sudo su enzotib -c 'echo "'\''aaa'\'' \"bbb\""'

sudo su enzotib -c "echo \\''aaa'\\'' \"bbb\"'"
sudo su enzotib -c "echo \"'aaa' \\\"bbb\\\"\""
9

Simple example of escaping quotes in shell:

$ echo 'abc'\''abc'
abc'abc
$ echo "abc"\""abc"
abc"abc

It's done by finishing already opened one ('), placing escaped one (\'), then opening another one (').

Alternatively:

$ echo 'abc'"'"'abc'
abc'abc
$ echo "abc"'"'"abc"
abc"abc

It's done by finishing already opened one ('), placing quote in another quote ("'"), then opening another one (').

Related: How to escape single-quotes within single-quoted strings? at stackoverflow SE

1

The accepted answer works for simple (one level) quoting:

$ echo $'\'single quote phrase\' "double quote phrase"'
'single quote phrase' "double quote phrase"

To get the command presented to work, you need to quote twice.
This script could do all the work:

#!/bin/bash

quote () { 
    local quoted=${1//\'/\'\\\'\'};
    printf "'%s'" "$quoted"
}

read -r line <<-\_line_to_quote_
'single quote phrase' "double quote phrase"
_line_to_quote_

quote "$line"; echo
quote "echo $(quote "$line")"; echo

Execute the script to get:

$ script
''\''single quote phrase'\'' "double quote phrase"'
'echo '\'''\''\'\'''\''single quote phrase'\''\'\'''\'' "double quote phrase"'\'''

The first line works for simple echo:

$ echo ''\''single quote phrase'\'' "double quote phrase"'
'single quote phrase' "double quote phrase"

The second line will work for the double quoted command:

sudo su USER -c 'echo '\'''\''\'\'''\''single quote phrase'\''\'\'''\'' "double quote phrase"'\'''
-1

echo 'I\'m a student' does not work. But the following works:

echo $'I\'m a student' From the man page of bash:

A single quote may not occur between single quotes, even when preceded by a backslash. .... Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard.

  • 4
    This adds nothing to the existing answers. – jasonwryan Jan 3 '18 at 5:55

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