Remove last character from string captured with awk [duplicate]

Question

I need to remove the last character from a string in this command:

sudo docker stats --no-stream 39858jf8 | awk '{if (NR!=1) {print $2}}'

The result is 5.20% , I need remove the % at the end, giving 5.20. Is it possibile to do this in the same command?

Answer 1

Yes, with substr() you can do string slicing:

... | awk '{if (NR!=1) {print substr($2, 1, length($2)-1)}}'

length($2) will get us the length of the second field, deducting 1 from that to strip off the last character.

Example:

$ echo spamegg foobar | awk '{print substr($2, 1, length($2)-1)}'
fooba