Docker - Give a variable to docker-compose

Question

I have a docker-compose.yml

php-fpm:
    build: ./php
    container_name: php-fpm-symfony
    links:
        - db
    ports:
        - 9000:9000
        - 8000:8000
    working_dir: /var/www/html/
    volumes:
        - ../:/var/www/html
    volumes_from:
        - data
    tty: true
    env_file:
        - ./docker.env
    entrypoint: /entrypoint.sh

When I'm executing my docker-compose up -d I would like to pass an argument, which is my container name, to name dynamically my container.

Is it possible with docker-compose?

Like for example:

docker-compose up -d "-variable=symfony" // ???

And:

php-fpm:
    build: ./php
    container_name: php-fpm-$(variable)

Something which works like that...

Answer 1

You can define all of your possible choices in YAML and use YAML references to keep the verbosity down.

default-container: &default-container
    build: ./php
    container_name: default
    links:
        - db
    ports:
        - 9000:9000
        - 8000:8000
    working_dir: /var/www/html/
    volumes:
        - ../:/var/www/html
    volumes_from:
        - data
    tty: true
    env_file:
        - ./docker.env
    entrypoint: /entrypoint.sh

php-fpm-symfony:
    <<: *default-container
    container_name: php-fpm-symfony

php-fpm-laravel:
    <<: *default-container
    container_name: php-fpm-laravel

References:

https://en.wikipedia.org/wiki/YAML#References

https://stackoverflow.com/questions/4150782/using-yaml-with-variables