Any advise on how to do delete all files and only keep the latest file in each sub-directories, starting from a specific directory? This is what I have tried:


find /home/ftp/ -type f | while IFS= read -r line
  find "$line" -type f | head -n -1 | while read file
    #rm -f "$file"
    echo "$file"

I have 2 sub-directories in /home/ftp/upload and /home/ftp/download. Both sub-directories have 2 files in each of the sub-directories.

When tested the script above, there is no file name echo out.

  • 3
    try something yourself first... if you are new to command line and shell scripting, have a look at stackoverflow.com/documentation/bash/topics and mywiki.wooledge.org/BashGuide .. or search online, lots of them are there – Sundeep Jul 25 '16 at 8:37
  • HINT: find $1 -type f -exec stat --format '%Y :%y %n' "{}" \; | sort -nr | cut -d: -f2- | head -n1 will list the latest file name. Use this logic to develop your script. If you fails at some point, do ask. – SHW Jul 25 '16 at 8:45
  • Edit that exact command into your question and specify what result you are getting and what result you expect. – Wildcard Jul 25 '16 at 8:51
  • Your first find should be -type d to select the directories. Note, though, that the second find doesn't order the results so you may end up keeping files at random, rather than "latest". – Stephen Harris Jul 25 '16 at 11:40

With zsh, from the current directory:

for dir (**/*(N/)) {
  (($#files > 1)) && echo rm -f -- $files[2,-1]

If you want hidden directories and files considered, add the D glob qualifier.

That only considers regular files. If you want other types of files like devices, sockets, named pipes, or if you want to follow symlinks, it can be adapted with more glob qualifiers.

Remove the echo to actually do the task.

With recent GNU tools and a POSIX shell:

(export LC_ALL=C
find . -type f -printf '%T@\t%p\0' |
  sort -rzn |
  cut -zf2- |
  gawk -v RS='\0' -v ORS='\0' '
    match($0,/.*\//) && n[substr($0,1,RLENGTH-1)]++' |
  xargs -r0 echo rm -f

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