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I have a script called operation.sh and while i am running the script, will be getting output like below and will wait for user input.

 1. Start
 2. Restart
 3. Stop
 4. Status
 Enter Option: 

Once I pressed "1", it will perform some logic and again it will come to above view.

I need to call the operation.sh from other sh (i.e., other.sh) like,

 sh other.sh

It has to perform the same logic as when I pressed 1 in operation.sh.

other.sh is having below content.

sh operation.sh 1

I could understand, it doesn't make sense (but I tried since I don't have any idea).

How can I call a menu script(which is performing action based on user selected menu) from another script.

  • Look at expect. – Henrik Jul 15 '16 at 14:50
  • @Henrik, i have't tried with expect. and I have idea. But, Is there any other way without using expect.? – Spike Jul 15 '16 at 14:54
  • Related: Prepare answers for questions of a command – steeldriver Jul 15 '16 at 14:59
  • depends on how the other script reads its input. for instance, for some ways that use standard input, echo 1 | sh other.sh might work – infixed Jul 15 '16 at 15:39
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#!/bin/sh 

OPC1() {
echo "Opcion 1"
}

OPC2() {
echo "Opcion 2"
}

SELECCIONA() {
if ( test $opc -eq 1 )
then
     OPC1
else
     OPC2
fi
}

#### MAIN ##########

opc=$1

if [ $1 ]
then
    SELECCIONA
else
    echo "1. start "
    echo "2. stop "
    echo "0. salir "
    read opc
    SELECCIONA
fi
  • i can't modify target script. can't i achieve my scenario without modifying target script? – Spike Jul 18 '16 at 4:55
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Try using echo -e "1\n2" piped to the script. Just put the menu responses separated by newlines (\n) in the string after -e.

echo -e "1\n2" | operation.sh

Another option is to put the responses in order one per line in a text file. You can then cat that file and pipe it to the script.

cat responses.txt | operation.sh

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