Unfortunately bc and calc don't support xor.
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4 Answers
Like this:
echo $(( 0xA ^ 0xF ))
Or if you want the answer in hex:
printf '0x%X\n' $(( 0xA ^ 0xF ))
On a side note, calc(1) does support xor as a function:
$ calc
base(16)
0xa
xor(0x22, 0x33)
0x11
answered Jun 27, 2016 at 10:26
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1In case your numbers are binary:
printf '0x%X\n' $(( 2#1010 ^ 2#1111 ))Feb 10, 2022 at 16:50
With any POSIX shell:
$ printf '%#x\n' "$((0x11 ^ 0x22))"
0x33
answered Jun 27, 2016 at 10:25
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2@StevenPenny, note that one difference with
0x%xis that it gives0instead of0x0for 0. Jul 27, 2020 at 11:36
gdb has powerful expression calculator:
gdb -q -ex 'print/x 0xA ^ 0xF' -ex q
A shell function:
calc_gdb() { gdb -q -ex "print/x $*" -ex q;}
calc_gdb 0xA ^ 0xF
$1 = 0x5
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4
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1Useful for the more general case of evaluating expressions, but not for XOR Jun 28, 2016 at 8:57
It is possible to do that in bc:
echo 'xor(10,15)' | bc -l logic.bc
Or in hex:
echo 'obase=16;ibase=16; xor(AA,FF)' | bc -l logic.bc
Using the logic file from here.
Just do wget http://phodd.net/gnu-bc/code/logic.bc to get it.
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Wow, that site is the
bc(1)geek's heaven. :) Thank you for the link. Jun 28, 2016 at 17:24 -
My version of "bc" doesn't seem to have the XOR function and just says:
Runtime error (func=(main), adr=51): Function xor not defined.– slacyOct 5, 2016 at 21:13 -
@slacy did you get the
logic.bcfile referenced there? That is what definesxorit seems Oct 11, 2016 at 17:53