Unfortunately bc and calc don't support xor.


With any POSIX shell:

$ printf '%#x\n' "$((0x11 ^ 0x22))"
  • %#x works in C too, nice! – Steven Penny Jun 27 '16 at 22:54

Like this:

echo $(( 0xA ^ 0xF ))

Or if you want the answer in hex:

printf '0x%X\n' $(( 0xA ^ 0xF ))

On a side note, calc(1) does support xor as a function:

$ calc
xor(0x22, 0x33)

gdb has powerful expression calculator:

gdb -q -ex 'print/x 0xA ^ 0xF' -ex q

A shell function:

calc_gdb() { gdb -q -ex "print/x $*" -ex q;}
calc_gdb 0xA ^ 0xF

$1 = 0x5
  • 4
    Amusing, but it seems like a sledgehammer to crack a nut! – abligh Jun 28 '16 at 8:16
  • 1
    Useful for the more general case of evaluating expressions, but not for XOR – Peter Cordes Jun 28 '16 at 8:57

It is possible to do that in bc:

echo 'xor(10,15)' | bc -l logic.bc

Or in hex:

echo 'obase=16;ibase=16; xor(AA,FF)' | bc -l logic.bc

Using the logic file from here.

Just do wget http://phodd.net/gnu-bc/code/logic.bc to get it.

  • Wow, that site is the bc(1) geek's heaven. :) Thank you for the link. – Satō Katsura Jun 28 '16 at 17:24
  • My version of "bc" doesn't seem to have the XOR function and just says: Runtime error (func=(main), adr=51): Function xor not defined. – slacy Oct 5 '16 at 21:13
  • @slacy did you get the logic.bc file referenced there? That is what defines xor it seems – Eric Renouf Oct 11 '16 at 17:53

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