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I read the book "understanding the Linux kernel". I cannot understand a sentence,that is ,the local CPU must have local interrupts enabled, otherwise kernel preemption is not performed. What is the meaning of this sentence?

  • Don't have that book, I would assume its saying that preempt is done when the CPU receives an interrupt—so with them disabled, it won't work. You could help someone with the book to give you a non-guess answer with some more details (e.g., some context from the book and also section or page number where that sentence occurs). – derobert Jun 14 '16 at 17:16
  • If you want a deeper guess, it implies that pre-emption switching from one process to another requires a timer to work, which requires an interrupt to run. – infixed Jun 14 '16 at 17:34
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If local (context implies "on This CPU") interrupts are forbidden, the (local) CPU will never see an interrupt to trigger possible kernel pre-emption.

  • but in function preempt_enable() which includes "if (!current_thread_info->preempt_count && !irqs_disabled()) { current_thread_info->preempt_count = PREEMPT_ACTIVE; schedule(); current_thread_info->preempt_count = 0; }". Why does the if statement chech whether the local interrupt is enabled by !irqs_disabled() – 80247617 aaa Jun 14 '16 at 19:19

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