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I am working on one shell script which search directory modified in last 24 hours and then compress them using tar.

Folder Search :

find /path to log directory/ -maxdepth 1 -type d -mtime +0 

example output:

/path to log directory/01_05_2016
/path to log directory/02_05_2016
/path to log directory/03_05_2016
/path to log directory/04_05_2016

Truncate unnecessary character:

find /path to log directory/ -maxdepth 1 -type d -mtime +0 | tr -d "_" | tr -d "path to log directory"

example output:

01052016 02052016 03052016 04052016

Separate the truncated strings as individual array element using "sed":

# Folder search

declare -a array="($(find <0-24 hour directory serach> | <truncate uncecessary character> | sed 's/\([0-9]*\).*/[\1]="\1"/'))"

# Array Printing
echo "Number of Array Elements: "${#array[@]}
echo "array[01052016]: " ${array[01052016]}
echo "array[02052016]: " ${array[02052016]}
echo "array[03052016]: " ${array[03052016]}
echo "array[04052016]: " ${array[04052016]}

example output

Number of Array Elements: 4
array[01052016]: 01052016
array[02052016]: 02052016
array[03052016]: 03052016
array[04052016]: 04052016

Compress the output:

LOG_DIR_NAME='<find folder>'

xargs tar -cvzPf /ouput folder/logname.tar.gz  /path to log directory $LOG_DIR_NAME

Problem Statment:

By the use of sed command, I can separate the search string into an individual array element. With the use of this command

sed 's/\([0-9]*\).*/[\1]="\1"/'

where [\1] defines my array index and "\1" defines my element.

Desired Output I am interested in getting the array element stored from index (0 to n)

array[0]: 01052016
array[1]: 02052016
array[2]: 03052016
array[3]: 04052016

How can I customize the array indexing in this case or traverse thru the array without knowing the start index?

Please help

Thank you

1

First of all, you should simplify your command to:

$ find "/path to log directory/" -maxdepth 1 -type d -mtime +0 | sed 's#.*/##; s#_##g' 
01052016
03052016
04052016
02052016

Next, to save as an array, you could just do:

array=( $(find "/path to log directory/" -maxdepth 1 -type d -mtime +0 | sed 's#.*/##; s#_##g') )

That saves it as you want, in an array with numerical, increasing indices starting from 0:

$ for i in {0..3}; do echo "$i : ${array[$i]}"; done
0 : 01052016
1 : 03052016
2 : 04052016
3 : 02052016

That said, if you do find yourself needing to iterate over an associative array, you can do that too:

$ declare -a array=( "foo"=>"bar" "baz"=>"bad" )
$ for i in ${!array[*]}; do echo "$i : ${array[$i]}"; done
baz : bad
foo : bar
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