sed substitution

Question

I have a string as follows:

/test/test/ 12 /test/test

My goal is to turn it into:

/test/est/ 12 /test/test

This is the command:

echo "$x" | sed 's@\(/*/\).@\1@g'"

I am using at the moment but it is applying it everywhere instead of at the second instance of "/"

could you please update your post and show us what is your string and what you want as a result ? Its unclear. — Rahul, Commented Apr 27, 2016 at 12:18
If you have GNU sed, you can replace just the nth match explicitly e.g. sed 's@/.@/@2' — steeldriver, Commented Apr 27, 2016 at 12:24

Sousa Gaspar · Accepted Answer · 2016-04-27 22:04:18Z

1

As stated by steeldriver, if you use GNU sed, you can tell which occurrence should be replaced, e.g.:

echo "/test/test/ 12 /test/test" | sed -n -e  's_/._/_2 p'

If you can not make use of this feature you can also write:

echo "/test/test/ 12 /test/test" | sed -n -r -e  's_(/[a-z]([a-z]+))\1_\1/\2_ p'

Biliography: http://www.grymoire.com/Unix/Sed.html [Using \1 to keep part of the pattern]

answered Apr 27, 2016 at 22:04

Sousa Gaspar

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sjsam · Accepted Answer · 2016-04-27 12:16:47Z

0

echo "/test/test/ 12 /test/test" | sed 's/\/test\/t/\/test\//'

answered Apr 27, 2016 at 12:16

sjsam

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jgshawkey · Accepted Answer · 2016-05-03 14:24:34Z

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Nice and easy...

sed -n "s/test/est/2p"

answered May 3, 2016 at 14:24

jgshawkey

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3 Answers 3