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I have a test.wav file.  I need to use this file to process an application, with following properties:

  1. monochannel
  2. 16 kHz sample rate
  3. 16-bit

Now, I'm using the following commands to attain these properties:

sox disturbence.wav -r 16000 disturbence_16000.wav
sox disturbence_16000.wav -c 1 disturbence_1600_mono.wav
sox disturbence_1600_mono.wav -s -b 16 disturbence_1600_mono_16bit.wav

Here to get a single file, three steps are involved and two temporary files are created.  It is a time-consuming process.

I thought of writing a script to do these process but I'm keeping this is a last option.

In single command, can I convert a .wav file to the required format?

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  • What should the -s-option do? Apr 4, 2016 at 8:43

2 Answers 2

19

sox disturbence.wav -r 16000 -c 1 -b 16 disturbence_16000_mono_16bit.wav

gives within one command

  • Sample rate of 16 kHz (-r 16000),
  • one channel (mono) (-c 1),
  • 16 bits bit depth (-b 16).
0

one-liner for all .wav files in the directory:

for file in *.wav; do sox $file -r 16000 -c 1 -b 16 "$(basename $file .wav)_16000_mono_16bit.wav" -V; done
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