bash - isolating uppercase words

Question

So, I have a directory containing around 50 directories having for name 3 letter uppercase words: AXC BCC EFC

amongst other directories.

I have already done a find to seek these 3 letter directories and store them in a list

list=`find /data/opr/ucansit/ -type d -name "???"`

The current output i get from an echo ${list[@]} is

/data/opr/ucansit/CUG /data/opr/ucansit/TGV /data/opr/ucansit/PAS

what i need now is seek the 3 letter directory names and store them in a stack as:

CUG
TGV
PAS

Note: I just need the names of the directories (the 3 letters)

BRegards,

If you don't need recursive, then (cd /data/opr/ucansit; set -- ???; printf '%s\n' "$@") is ok — cuonglm, Mar 24 '16 at 9:34

jlliagre · Accepted Answer · 2016-03-24 09:16:54Z

0

Here is one way to do it:

list=$(find /tmp /data/opr/ucansit/ -type d -name "???" -exec basename {} \;)
printf "%s\n" "${list[@]}"

answered Mar 24 '16 at 9:16

jlliagre

49.7k9 gold badges91 silver badges142 bronze badges

find /tmp /data/opr/ucansit/ -type d -name "???" -printf "%f\n" – Costas Mar 24 '16 at 9:21
Perfect . Exactly what I needed! – scandalous Mar 24 '16 at 9:28
@Costas Beware that "-printf" only works if GNU find is used. – jlliagre Mar 24 '16 at 11:07

add a comment |

1 Answer 1