I love to type bash scripts, but if I prepare multiple tools, project's root directory is filled with so many shell scripts. That's why I prefer using Makefile.

Makefile is good. However I want to build my makefiles just as regular bash scripts.


Think that I wrote a bash script very quickly with the following content:

echo "hello"
cd ~
do-some-work.sh my-parameter

I can run this script with $ ./my-important-task.sh.

If I wanted to move that script into makefile, I should do the following:

SHELL := /bin/bash 

    echo "hello" ;\
    cd ~ ;\
    do-some-work.sh my-parameter

but I want the following:

    [[copy and paste the my-important-task.sh file]]

Is there anyway to accomplish this goal?

4 Answers 4


If you really want to “write exactly bash scripts into Makefiles” then you'll need to do it a bit indirectly. If you just paste the script after the target line, then you'll run into two problems that just cannot be bypassed: the command lines need to be indented with a tab, and dollar signs need to be escaped.

If you use GNU make (as opposed to BSD make, Solaris make, etc.), then you can define your script as a variable using the multi-line definition syntax, and then use the value function to use the raw value of the variable, bypassing expansion.

In addition, as explained by skwllsp, you need to tell make to execute the command list for each target as a single shell script rather than line by line, which you can do in GNU make by defining a .ONESHELL target.

define my_important_task =
# script goes here

my-important-task: ; $(value my_important_task)

  • Would you mind taking a look at this file: gist.github.com/ceremcem/a380bb92cbd03c34aba5
    – ceremcem
    Mar 19, 2016 at 0:37
  • 1
    @ceremcem You need .ONESHELL as well. Mar 19, 2016 at 11:34
  • 1
    When using .ONESHELL, probably want to start the recipe with 'set -e'. Without ONESHELL the recipe will abort on first error; but with ONESHELL (and SHELL = /bin/bash) the recipe will not abort on error. 'set -e' goes back to abort on error
    – steve
    Feb 20, 2021 at 22:26
  • This is very useful to be able to have a bash code snippet inside the makefile. How to I access the variables from makefile within the script. Or is there a way to pass a variable to 'my_important_task'
    – Nazar
    Mar 8 at 19:30
  • You can export a make variable to the environment. Look up export in the GNU make manual. Mar 8 at 21:02


If the .ONESHELL special target appears anywhere in the makefile then all recipe lines for each target will be provided to a single invocation of the shell.

You will still need to put a tab character at the beginning of each line, and to double all dollar signs (i.e. replace $ by $$ everywhere in the script).


If the problem is that your top-level project directory is cluttered with dozens of scripts, then the obvious solution is to create a subdirectory (e.g. called scripts) to put them in.

Run them as ./scripts/scriptname and/or add the scripts directory to your PATH.

If you still want a Makefile to run them with, just create Makefile entries that run ./scripts/scriptname for those targets. e.g.

    ./scripts/my-important-task.sh my-parameter

NOTE: If the scripts in ./scripts call other scripts in the same directory, they'll need to either specify the full path to the script, or have the scripts directory in the PATH.

  • Maybe that would be an appropriate solution. But writing down in a single file would make things speed up in most cases. We were talking about a proposal yesterday though...
    – ceremcem
    Mar 19, 2016 at 10:49
  • somehow i doubt very much that having make parse a Makefile, search for a target, and then fork a shell to run some shell commands could possibly be faster than just running a shell script. not that the startup speed of make plus a bunch of shell commands or a shell script is at all significant on any modern-ish machine (say, less than 20 years old) unless run thousands of times in a loop.
    – cas
    Mar 19, 2016 at 11:33

You can use aliases and functions defined in your .bashrc (and possibly .bash_aliases).

  • This is not an answer, but a comment.
    – ceremcem
    Jun 19, 2019 at 8:48
  • OK, now it's an answer...
    – xenoid
    Jun 19, 2019 at 9:00
  • 2
    .bashrc is not an alternative to Makefile. Makefile's are meant to be used in development process and always distributed by the application code.
    – ceremcem
    Jun 19, 2019 at 9:17

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