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How can I find a number of files in a folder, assign it to a variable, then echo that variable, all in one command line?

marked as duplicate by don_crissti, Jeff Schaller, vonbrand, Anthon, Jakuje Mar 1 '16 at 16:28

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  • Do you want to include sub-directories in this count? – Centimane Mar 1 '16 at 15:40
  • @Dave yes including subdirectories – Warrior4just Mar 1 '16 at 16:12
  • Any type of file? Or just regular files? Excluding directories? What about symlinks (to regular files or others). What about files (hard-)linked several times (or in other words, do you want to count files or directory entries)? What about the . and .. entries? Do you want them included? – Stéphane Chazelas Mar 1 '16 at 16:20
  • @StéphaneChazelas jus regular files within a parent directory and its subfolders . – Warrior4just Mar 1 '16 at 16:28
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linecount=$(find /folder/name/here/ -type f | wc -l); echo ${linecount}

is the simplest way of doing this. it counts every file in the folder and its sub-folders.

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    This isn't correct in the presence of files or directories with carriage returns in their filenames. – pericynthion Mar 1 '16 at 15:43
  • @pericynthion, carriage return wouldn't be a problem, linefeed aka newline would though. – Stéphane Chazelas Mar 1 '16 at 17:02
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What comes to my head without using semicolon to break and start a new command is to use Parameter substitution with Command substitution

$ echo ${filecount=$(find . -type f | wc -l)}

Then you can echo the variable again and you can confirm the result.

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