Bash script tar specific files with retention period

Question

I am new to bash script. I need to keep file for retention period of one month and archive other.

Example:

File format: WE20160225.log (20160225 YYYYMMDD)

Say in the directory /oracle/Sales has 2 files:

WE20160130.log

WE20151201.log

I need to tar the WE20151201.log

But not WE20160130.log because the file is less than one month from now. How can I do this? (probably need to substring the filename)

I'm able to change directory but don't know what to do next. My logic is loop through the file and get the date from filename, then compare with current date.

I need to use the filename date, not the file modification date.

SALES_DIR="/oracle/sales/"
cd $SALES_DIR

Answer 1

I use something like this:

find <dir> -name <pattern> -mtime <timeframe> -exec <cmd> <options> {} \;

find . -type f -name '*log*' -mtime +10 -exec tar -rvf backup$(date +"%m-%d-%y") {} \;

finds files with log in their name that are older than 10 days. Creates a tar archive with todays date and appends all the files. You could also do away with the $date and append only new files, then semicolon and remove the file with rm {} \;

Answer 2

You can use something like this:

find somedir/* -mtime +5 -exec rm {} \;

It used find to find files older than 5 days and passes the found file over to delete.

Answer 3

Here is the script for compressing month old log files.

#!/bin/bash
files=($(find /oracle/Sales -mtime +30))
tar cvfz backup.tar.gz "${files[@]}"

-mtime +number-of-days to describe the file which you need to backup.

For deleting the older file try this

find /oracle/Sales -mtime +30 | xargs -n1 echo rm

If you get the right output then remove echo from the line.