How can I print all the lines between two lines starting with one pattern for the first line and ending with another pattern for the last line?
I guess it was a mistake to mention that this document is HTML. I seem to have touched a nerve, so forget that. I'm not trying to parse HTML or do anything with it other than print a section of a text document.
Consider this example:
aaa bbb pattern1 aaa pattern2 bbb ccc pattern2 ddd eee pattern1 fff ggg
Now, I want to print everything between the first instance of
pattern1 starting at the beginning of a line and
pattern2 starting at the beginning of another line. I want to include the
pattern2 lines in my output, but I don't want anything after the
pattern2 is found in one of the lines of the section. I don't want to stop there, but that's easily remedied by indicating the start of the line with
pattern1 appears on another line after
pattern2, but I don't want to look at that at all. I'm just looking for everything between the first instance of
pattern1 and the first instance of
I found something that almost gets me there using
sed -n '/^pattern1/,/^pattern2/p' inputfile.txt
... but that starts printing again at the next instance of
I can think of a method using
grep -n ... | cut -f1 -d: twice to get the two line numbers then
head to get the section I want, but I'm hoping for a cleaner way. Maybe
awk is a better tool for this task?
When I get this working, I hope to tie this into a
git hook. I don't know how to do that yet, either, but I'm still reading and searching :)