Cron Job Hourly Except Certain Time Frame on Friday

Question

I want my cron job to run every hour, every day except Friday when I don't want it to run at all between the hours of 2am-9am (but hourly outside of this timeframe). Ideally, I'd like to have this in one line/one cron job. What I have so far is 2 lines (and I'm not 100% sure it is correct):

0 0 * * 0,1,2,3,4,6 script.sh
0 0-1,10-23 * * 5 script.sh

Answer 1

The format seems to be correct (after correction applied posted in the comment above). Are there some special restrictions for having everything in a single line? In case you need to have everything in a single line, I would suggest to change the shell script to avoid Fridays 2-9am, eg

#!/bin/bash
# THIS CODE IS NOT TESTED
# skip on fridays 2-9am
# what are the non-running times?
STARTTIME=2
ENDTIME=9

# get the current day of the week
DAY=$(date +"%u") # 1-Monday, therefore 5-Friday
# and the hour
HOUR=$(date +"%H")

if [ "$DAY" -eq 5 -a "$HOUR" -ge "$STARTTIME" -a "$HOUR" -le "$ENDTIME" ]
then
   # end the execution
   exit 0
fi

Hope that helps to solve the issue!

Frank