How to split up embedded Ruby string in shell command

Question

Writing a web2py on Cloud SQL boon using Gitbookl. It contains the following line of OSX bash shell code:

$ ruby -e "$(curl -fsSL https://raw.githubusercontent.com/Homebrew/install/master/uninstall)"

Would like to shorten the display to 40-60 characters per line while still allowing the user to copy and paste the code in. All of my experiments are failing, but obviously I want to do something like this:

$ ruby -e "$(curl -fsSL\
https://raw.githubusercontent.com/\
Homebrew/install/master/uninstall)"

No longer a Ruby guy and am at wit's end. Can someone tell me how to get a copy/pasteable line like this into my markdown?

(The general problem is that ebooks are limited to 40-60 columns in code printouts, and I need a way to handle long paths and long paths.)

Answer 1

You can also do:

$ curl -fsSL https://raw.githubusercontent.com/\
Homebrew/install/master/uninstall|ruby

Answer 2

Something like this should to the trick..

domain="raw.githubusercontent.com"
url="Homebrew/install/master/uninstall"

ruby -e "$(curl -fsSL https://${domain}/${url})"

Answer 3

steeldriver nailed it. The answer was to insert a space before the slash at the end of the first line, so:

ruby -e "$(curl -fsSL \
https://raw.githubusercontent.com/\
Homebrew/install/master/uninstall)"

That can indeed be copy and pasted right into the shell prompt.

As soon as the Nobel committee sees fit to make me one of their own I am going to nominate steeldriver for something.