getting file name from the input path to the file in shell scripts [duplicate]

Question

Possible Duplicate:
Best way to remove file extension from a string?

Say that I have a script called script.sh

In the shell I type

script.sh ../folder/file.py

and in that file I know echo $1 will output ../folder/file.py

But is there anyway of getting just the filename without the extension... file only?

Answer 1

BASH has a number of string operators you might want to use here, but I don't see how to do it in just one, so you can either use two statements, or a subshell:

echo `basename ${1%.py}`

Or, more generally,

echo `basename ${1%.*}`

Or, with a temporary variable:

FILE=${1##*/}
echo ${FILE%.*}

I suppose, as long as you're using a subshell, sed will work too.

echo `echo $1 | sed 's/.*\/\([^/]*\)\(\.[^./]*\)\?/\1/'`

That's a somewhat ugly expression, but it could be cleaned up if you made some assumptions about the input.

Answer 2

if your extension is always delimited by the point and filenames does not have point(s) inthere, you could use the simple way :

echo $(basename $1) | cut -d. -f1

But definitly the best way is the one described above by Kevin.