NOTE: This question is the complement of this Q&A: How to "grep" for line length in a given range?
How can we grep for lines that have less than 8 or more than 63 characters, none that contain more than eight and less than 63 characters?
So, some acceptable character counts could be...
7 6 5 4 3 2 1 0
...and...
64 65 66 67 ...
grep -xv '.\{8,63\}' <input >output
grep's -x switch denotes a whole line match - which is to say that any pattern matched must define a line from head to tail. doing...
grep -x pattern
...is generally equivalent to...
grep ^pattern$
grep's -v switch negates a pattern's influence on line-selection. generally doing...
grep pattern
...will only select lines that match the pattern, but with a -v negated pattern only those lines that don't match are selected.
...and so...
grep -xv '.\{8,63\}'
...matches all lines which consist from head to tail of anywhere between 8 and 63 characters, and the -v negated selection causes grep only to print everything else.
grep, but you may considerawk, especially if you need further processing, etc (very flexible, and readable):awk '( length($0)<8 ) || ( length($0)>63 )'#default action of a condition is to print the line(s) matching the condition . Or, with less processing on $0:awk '{ l=length($0) ; if (( l<8 ) || l>63 ) { print $0 ;} }'