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I have a file with a lots of names etc. and with spaces in between. Now, I want to delete all trailing spaces and all empty lines in this file with sed.

I have two commands for this task but I would like to have a combination of both:

sed -i's/\s*$//g' 
sed -i'/^$/d'
  • You mean sed -i 's/.../.../;/^$/d'? – Joseph R. Dec 13 '15 at 22:24
  • sed -ne '/[^ ]/s/ *$//p' – mikeserv Dec 13 '15 at 22:28
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With GNU sed (and probably others), you can give multiple commands separated by a semicolon:

sed -i 's/\s*$//g; /^$/d'

Other sed implementations might need you to give the two commands separately with -e:

sed -i -e 's/\s*$//g' -e '/^$/d'

Finally, you could also combine them into a sed script:

$ cat foo.sed
s/\s*$//g
/^$/d

Then, you run it with -f:

$ sed -i -f foo.sed file
2

this is the command you are looking for:

sed -ne '/[^ ]/s/ *$//p' <in >out

... for lines which match at least least 1 not-space character, sed will susbstitute away the longest match it can make of 0 or more trailing spaces on the tail of the line. if successful (and it always will be, because there's never a shortage of nothing), the line is printed.

the result is that command prints only not-space and not-blank lines while simultaneously trimming all trailing spaces.

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