C Shell Script syntax error “unexpected end of of file”

Question

I am trying to write a c-shell script that checks for number of arguments and echos a string, but I am getting an unexpected end of file syntax error and I don't understand why.

Here is what I tried:

if ( $#argv == 0 ) then
echo "Enter one or more args"
else
echo "Entry accepted"
endif

Later I tried to output each argument found with this:

if ( $#argv == 0 ) then
echo "Enter one or more args"
else
  foreach arg ( $* )
    echo "Found argument $arg"
  end 
endif

and got a different syntax error "unexpected token `('"

Any help is appreciated

Answer 1

Agreeing with comment by @mark-plotnick, OP has to ensure that the script is run by csh, e.g., by adding the "hash-bang" line:

#!/bin/csh

or running the script using the appropriate program:

csh ./foo

As a general rule, if a script lacks this information it will be run using /bin/sh

Further reading:

• The #! magic, details about the shebang/hash-bang mechanism on various Unix flavours
• 3.16) Why do some scripts start with #! ... ? Unix - Frequently Asked Questions (3/7)