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I want append some lines through a bash script with sed. The script works but the output is wrong.
LINEB="word"
sed '/g id=\"..\"/a style=\"fill:$LINEB;\"' file.txt > foo.txt
I get <g id="ai" style="fill:$LINEB;"> instead of <g id="ai" style="fill:word;">
Even if I use all kinds of parenthesis.
You can't embed a variable inside single-quotes. You could:
use double-quotes around the entire sed script, and backslash-escape all the double-quotes inside it.
end the single-quoted string with a ', double-quote-the variable, and then re-start the single-quoted string again:
LINEB="word"
sed '/g id=\"..\"/a style=\"fill:'"$LINEB"';\"' file.txt > foo.txt
sed: -e expression #1, char 66: extra characters after command
Nov 29, 2015 at 21:55
First, you need to take care that $LINEB is properly prepared for a sed append command:
sed '/<\([^"<>]*\("[^"]*"\)* \)*g id="[^"][^"]"/a\'"$(echo;#"'
printf 'style="fill:"%s"\n' "$LINEB" |
sed 'H;1h;$!d;s/\\/&&/g;s/\n/\\&/g')
" <infile >outfile
It might also be easier to locate the appended text in another file that you can then read in whenever appropriate:
printf 'style="fill:%s"\n' "$LINEB" >/tmp/LINEB
sed '/<\([^"<>]*\("[^"]*"\)* \)*g id="[^"][^"]"/r /tmp/LINEB' <infile >outfile
rm /tmp/LINEB
This requires no escaping.
/a.