Extract a List of .zip files into one new directory each, directory name to be taken from name of the zip file

Question

I have a folder containing many .zip files. They are named like this:

John-Rupert A. Doe_nnnnnnn_assignsubmission_file_*.zip

where n is a digit, * is a string and John-Rupert A. Doe is a string that may contain spaces, dots and dashes.

For each of them, I want to do the following:

1. create a directory. I do this via:

   ls | cut -d'_' -f 1 | sed 's/ //g' | tr -d '.' | tr -d '-' | xargs -L 1 mkdir
   

   (So, the corresponding directory name for the example above would be JohnRupertADoe)

2. Now I want to extract each .zip file into the directory created using this .zip file name. But how?

Answer 1

You could try with:

for z in ./*.zip
do name="${z%%_*}"; dest=".${name//[ .-]/}"; mkdir "$dest"; unzip "$z" -d "$dest"
done

For each zip file it extracts the name part ( ${z%%_*} deletes suffix greedily) it then removes any occurrence of dot, dash and space (${name//[ .-]/}) and passes the resulting string as an argument to mkdir to create the corresponding directory. It then unzips the archive to the specified destination.

Answer 2

Untested:

for i in *.zip; do
  zipdir() { echo "$i" | cut -d'_' -f 1 | sed 's/ //g' | tr -d '.' | tr -d '-'; }
  zipdir | xargs -L 1 mkdir
  mv "$i" "$(zipdir)"/
done

Or to remove both tr pipes, you could just add to your pipe to sed (also untested):

for i in *.zip; do
  zipdir() { echo "$i" | cut -d'_' -f 1 | sed 's/ //g;s/.//g;s/-//g'; }
  zipdir | xargs -L 1 mkdir
  mv "$i" "$(zipdir)"/
done