2

I have a word and I want to check what the percent of its appearance in a file ( according to the total number of word in the file ) ? For example if I have the word "you" and it appears 2 times in a file with 8 words the output will be 25%.

I tried: fgrep -ow

Improve this question
0
2

you can get the total numbers of words in your file as follow

nw=`wc -w < /path/to/file`

And the number of occurrences of a certain word/pattern with

occurrences=`egrep -c <pattern> /path/to/file`

then you can easily calculate the percentage and put the result in a variable

result=`echo "scale=2; $occurrences*100/$nw" | bc`

to add the % you can eg. do as follow

echo $result'%'
Improve this answer
2
  • tnx!! but how i can sdd % near the result? – mor Nov 11 '15 at 21:25
  • you welcome, it was funny to test, i ll update the answer ; ) – lese Nov 11 '15 at 23:29
0

Use the same logic as shown URL

tr ' ' '\n' < file.txt | awk '{if($0=="her"){nmw+=1}}END{print ((nmw*100)/NR)}'
Improve this answer
3
  • Assumes all words are separated by spaces. – 123 Nov 11 '15 at 10:31
  • tnx, but for some reason it not working, it gives me 0 as output. what is "her" ? – mor Nov 11 '15 at 10:35
  • replace her with string you want to search so for your case it is you. – jijinp Nov 11 '15 at 11:29
0

With awk:

awk -vw="word" 'BEGIN{RS="[^a-zA-Z]+"} $0==w{c++} END{printf "%.1f%%\n",c*100/NR}' file
  • -vw="word" gives awk the variable w which contains "word". That is the word, you want to have the percentage.
  • BEGIN{RS="[^a-zA-Z]+"} sets the row separator to everything, but letter, so every word is processed separately.
  • $0==w{c++} increase the counter if the word is found.
  • END{printf "%.1f%%\n",c*100/NR} print the calculated number after the file is processed
Improve this answer

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.