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I have a word and I want to check what the percent of its appearance in a file ( according to the total number of word in the file ) ? For example if I have the word "you" and it appears 2 times in a file with 8 words the output will be 25%.

I tried: fgrep -ow

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you can get the total numbers of words in your file as follow

nw=`wc -w < /path/to/file`

And the number of occurrences of a certain word/pattern with

occurrences=`egrep -c <pattern> /path/to/file`

then you can easily calculate the percentage and put the result in a variable

result=`echo "scale=2; $occurrences*100/$nw" | bc`

to add the % you can eg. do as follow

echo $result'%'
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  • tnx!! but how i can sdd % near the result? – mor Nov 11 '15 at 21:25
  • you welcome, it was funny to test, i ll update the answer ; ) – lese Nov 11 '15 at 23:29
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Use the same logic as shown URL

tr ' ' '\n' < file.txt | awk '{if($0=="her"){nmw+=1}}END{print ((nmw*100)/NR)}'
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  • Assumes all words are separated by spaces. – 123 Nov 11 '15 at 10:31
  • tnx, but for some reason it not working, it gives me 0 as output. what is "her" ? – mor Nov 11 '15 at 10:35
  • replace her with string you want to search so for your case it is you. – 7171u Nov 11 '15 at 11:29
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With awk:

awk -vw="word" 'BEGIN{RS="[^a-zA-Z]+"} $0==w{c++} END{printf "%.1f%%\n",c*100/NR}' file
  • -vw="word" gives awk the variable w which contains "word". That is the word, you want to have the percentage.
  • BEGIN{RS="[^a-zA-Z]+"} sets the row separator to everything, but letter, so every word is processed separately.
  • $0==w{c++} increase the counter if the word is found.
  • END{printf "%.1f%%\n",c*100/NR} print the calculated number after the file is processed
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