md5sum for every file (with ll)

Question

I want output like this: name size and hash:

myfile.txt 222M 24f4ce42e0bc39ddf7b7e879a
mynewfile.txt 353M a274613df45a94c3c67fe646

For name and size only I have

ll -h | awk '{print $9,$10,$11,$12,$5}'

But how can I get hash for every file? I tried:

ll -h | awk '{print $9,$10,$11,$12,$5}' | md5sum

But I get only one hash at all.

Answer 1

You should not parse ls, instead use this:

for f in * .*; do
  [ -f "$f" ] && \
    printf "%s %s %s\n" "$f" $(du -h -- "$f" | cut -f1) $(md5sum -- "$f" | cut -d' ' -f1)
done

• The for loop runs trough all files and directories in the current directory.
  • [ -f "$f" ] checks if it's a regular file
  • printf "%s %s %s\n" prints the arguments in the desired format.
  • "$f" the first argument is the filename
  • du -h -- "$f" | cut -f1 the second is the size (human readable), but not the filename, cut cuts all excep the first field away
  • md5sum -- "$f" | cut -d' ' -f1 third is the MD5 sum, but without the filename.