I have a set of nested zip files and I need to list the file names without extracting the archives. For example:
with some shell scripting should result in a list such as
Zip1.zip
Zip1.zip/text1
Zip1.zip/text2
Zip1.zip/Zip2.zip/Sample1
Zip1.zip/Zip2.zip/Sample2
The unzip -p flag will pipe the uncompressed data to stdout. Unfortunately the unzip program doesn't have an option to read from stdin for some reason. Adapting the python one liner from this answer to a similar question does the trick.
eg:
unzip -p Zip1.zip Zip1/zip2.zip| python -c 'import zipfile,sys,StringIO;print "\n".join(zipfile.ZipFile(StringIO.StringIO(sys.stdin.read())).namelist())'
Added: The Java jar tool can read from stdin. stolen from this answer.
eg:
unzip -p Zip1.zip Zip1/zip2.zip| jar -t
output:
zip2/
zip2/Sample2
zip2/Sample1
original zip file:
$ unzip -l Zip1.zip
Archive: Zip1.zip
Length Date Time Name
--------- ---------- ----- ----
0 2015-11-03 15:49 Zip1/
5 2015-11-03 15:49 Zip1/text1
5 2015-11-03 15:49 Zip1/text2
474 2015-11-03 15:48 Zip1/zip2.zip
--------- -------
484 4 files
Found the relevant Serverfault thread from your - comment.
This isn't a shell script, but it does what was suggested in the original question:
#!/usr/bin/python
# Usage: python list-zips.py <zipfile>
import zipfile
import io
import sys
def uz(f, parent=[]):
result = []
try:
zf = zipfile.ZipFile(f)
for e in zf.namelist():
path=parent+[e]
if e.lower().endswith(".zip"):
result += uz(io.BytesIO(zf.open(e).read()), path)
else:
result.append("/".join(path))
except Exception as ex:
return result
return result
print("\n".join(uz(open(sys.argv[1], "rb"), [sys.argv[1]])))
$ python list-zips.py Zip1.zip
Zip1.zip/text1
Zip1.zip/text2
Zip1.zip/Zip2.zip/Sample1
Zip1.zip/Zip2.zip/Sample2
