-1

This is my sed command:

while ...;
do sed -r "${counter}s/^\S+ /$line /g" $in > $out;
..
..
done

Unfortunately this command isn't doing anything when called from within a bash script/loop. So I thought to check if the variables are being resolved the right way:

do echo ´sed -r "${counter}s/^\S+/$line/g" $in > $out´;

which printed this to the console:

sed -r <line number>/^\S+/<replace pattern>/g <infile> > <outfile>

When executing this very command (without the ´) from the console, I get this:

sed: -e expression #1, char 8: unterminated s' command

I guess this is because the ' are missing around the pattern.

So how do I combine double (for resolving variables in sed command) and single (for completing the search/replace pattern) quotation marks when calling this from a bash script?

  • how could it possibly work? i dont see any input at all, and it looks like youre calling sed to work a single line at a time. if thats the case then $counter wont ever work for any line at all but line 1. you really shouldn't loop like that - its spidery and wasteful. think in terms of a chain instead of in terms of a home base. if you do: while gen ouput; do :; done | sed 's/edit/the_whole_stream/' you'll be a lot better off. – mikeserv Oct 28 '15 at 9:46
  • $counter is being raised after the sed command. So that is one working. Yes, I'm want to call sed for each line, because I got a file A and file B. The beginning of line in file B should be replaced with the beginning of line in file A.Those chars differ in each line. – entenbein Oct 28 '15 at 9:57
  • awk or perl are better tools for doing that. – cas Oct 28 '15 at 10:02
  • 1
    Is there / or \n in $line variable? Any way try to execute sed -r "<line number>/^\S+/<replace pattern>/g" <infile> > <outfile> for testing purpose. Is it doing what you wants? – Costas Oct 28 '15 at 10:16
  • Hi, no such thing in $line. The command itself with expanded/resolved variables works fine. Calling the mentioned command with the line number from a variable isn't working so far. – entenbein Oct 28 '15 at 10:25
-1

Well, that is strange. The redirect to the output file didn't happen, at least not with the expected replacements. A cp <infile> <outfile> with the following sed replace command inplace works like a charm....

Thanks for your help!

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