How to run Java program in Bash script and give it one argument?

Question

I will add an item on a context menu, called "Open with ABC". This context menu appear when I right-clicked a folder.

When the "Open with ABC" is selected, it will launch a Java program, "abc.class".

That Java program need "directory path" of that chosen folder, as argument.

How my Bash script will look like?

Informations you might need:

• java: usr/bin/java
• abc Java program: home/john/myapp/abc.class
• The script will be put inside home/john/.config/caja/scripts
• The john is my username for Linux Mint MATE 17.2, with caja as file manager

Below questions might close to my problem:

• https://stackoverflow.com/questions/14601430/how-to-run-a-c-program-in-bash-script-and-give-it-2-arguments

• Mandatory argument for script to run java program

• http://forums.mate-desktop.org/viewtopic.php?f=17&t=812

Answer 1

There is Caja-actions Configration tool to add the open with ABC in context menu.

There is command tab in Caja Action tool, there you can provide the script path and the directory argument. Here is a image of the tool http://poundbangbinbash.com/LinuxMint/MATE/Caja/CajaActions/ConfigurationTool.png

your script would look like

!/bin/bash
usr/bin/java [options] home/john/myapp/abc.class $*

Answer 2

My Bash script looks like this:

#!/bin/bash
java -cp "$HOME/myapp" abc $CAJA_SCRIPT_SELECTED_FILE_PATHS

Explanations:

Since my program was placed inside here:

/home/john/myapp/abc.class

• I must always use -cp java options to locate my "abc" program first.
• The $HOME represents my home directory, /home/john,
• The $CAJA_SCRIPT_SELECTED_FILE_PATHS environment variable represents the path of the folder I selected, which eventually being passed as argument to "abc" program.

Note that these solution is made in caja specific environment - no guarantee to work in elsewhere.

Credits to @pranav, thanks.