is it possible to print the field that contain a certain value?

Consider below file:


There is a field that contain ABC but it is not a fixed with all records, so the command need to print $5 in the first record and $3 in the second one.

  • 1
    It sounds to me like this could be simplified to grep -q ABC file && echo ABC ? – Jeff Schaller Oct 3 '15 at 13:24
  • What you described is print ABC if record contains ABC. Is this what you want. – ctrl-alt-delor Oct 3 '15 at 14:25

Yes, just like in your previous question, but match each field:

$ awk -F, '{for(i=1;i<=NF;i++){if($i~/ABC/){print $i}}}' file

Note that the above will also print a filed that contains ABC, like fooABC or fooABCbar or whatever. To print only fields that are ABC, use:

awk -F, '{for(i=1;i<=NF;i++){if($i=="ABC"){print $i}}}' file

The same thing, in Perl:

perl -F, -lane 'print grep{/ABC/}@F' file     ## field matches
perl -F, -lane 'print grep{$_=="ABC"}@F' file ## field is

You can use grep with PCRE (Perl Compatible RegEx):

grep -Po '(?<=^|,)ABC(?=,|$)' file.txt
  • 1
    For most cases is enough '\bABC\b' regexp – Costas Oct 3 '15 at 12:59

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