2

I have this if statement and every time I change something another thing seems to be wrong. Can you see the problem?

if [[ $(ps -ef | grep "Process" | grep -v "grep" | awk '{print $2}') = '' ]]; then
        echo "bien"
fi

I get launcher.sh[74]: 11927676^J15335522: syntax error

  • I guess you are missing the $ in (ps. It should be $(ps. Also add what you have tried and the errors you are having to the question. – BitsOfNix Oct 1 '15 at 11:07
  • it doesn't work.. :( – lucia Oct 1 '15 at 11:18
2

If "Process" is a fixed string, try

ps -ef | awk '/[p]rocess/ {print $2}'

to get process id.

If you are checking for a missing process ( ... = '' )

if ps -ef | grep -q [P]rocess
then 
   echo Process present
else
   echo Process absent
fi

You might also have a look at pgrep(1) (e.g. man pgrep )

0

Comparison in KSH needs to be done with two equal signs. ==

if [[ $(ps -ef | grep "Process" | grep -v "grep" | awk '{print $2}') == '' ]]; then
        echo "bien"
fi

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