I have the following text in the data.txt file
:MENU1 0. public 1. admin 2. webmail :SYNTAX ! opt1, ... : :ERROR1 Error #1, blah... blah.. blah... Please do ... :ERROR2 Error #2 ...
and I want to use a regular expression (PERL syntax) to extract the part from
:MENU1 to the next first
:, but dropping
MENU1 and the last
: from the result.
Been trying several regex's but in the closest solution I got I can't put the 'greedy' option to work and cant't discard the last ":"
grep -Poz "^:MENU1\K[\w\W]*:"
this works with grep ...
but brings all the text until the last ":" ...
I want only until the next first ":" after
0. public 1. admin 2. webmail
(note the final blank line)