I am trying to replace a string from a file which contains '&' in its value.

vari = '111|abc & efg|123'
varj = '222|abc & efg|123'

echo $vari | sed -e "s/$vari/$varj/g"

output is 222|abc 111|abc & efg|123 efg|123

I don't know how to handle '&' in find and replace variable. Can anyone help?

  • Just to add that i am doing this in korn shell – girish chalke Sep 29 '15 at 7:26

The & character in $varj has a special meaning in the replace portion of an s/search/replace/ command. It means "insert the matching text here".

You can use \& to 'escape' the & so it doesn't have a special meaning. You can use sed to modify $varj to replace all & chars with \&:

varj=$(echo "$varj" | sed -e 's/\&/\\\&/g')

For example:

cas@ganesh:/tmp$ ksh
$ vari='111|abc & efg|123'
$ varj='222|abc & efg|123'

$ echo "$vari" | sed -e "s/$vari/$varj/g"
222|abc 111|abc & efg|123 efg|123

$ varj=$(echo "$varj" | sed -e 's/\&/\\\&/g')
$ echo "$varj"
222|abc \& efg|123

$ echo "$vari" | sed -e "s/$vari/$varj/g"
222|abc & efg|123
| improve this answer | |
  • super stuff. Worked – girish chalke Sep 29 '15 at 8:54
  • Or (with {ba,k,z}sh) simply: sed "s#${vari}#${varj//&/\\&}#g" – don_crissti Sep 29 '15 at 17:46

You need escape the & character in the replacement text. This is because & is a special character for the replacement text. So let your $varj be as follows.

varj = '222|abc \& efg|123'

You can then call sed as follows.

echo $vari | sed -e "s/$vari/$varj/g"
| improve this answer | |
  • vari is a line from a file and i am not able to substitute anything in this line because of '&' – girish chalke Sep 29 '15 at 7:37
  • @girishchalke no, it is not because of the &. Just insert the \ as shown in the answer and it will work. – nehcsivart Sep 29 '15 at 7:48
  • this problem has nothing to do with spaces. even if it did, the correct way to deal with it would be to use double-quotes whenever using (e.g. echo-ing) $vari or $varj. e.g. echo "$vari" | sed .... In fact, as a general rule it is almost always best to use double-quotes around variables except in the very few instances where you know precisely why you don't want to use quotes. – cas Sep 29 '15 at 8:32
  • @tchem. Tried your recommendations but still no success. Just to ensure its not because of '&', i removed it and kept space as it is. vari="111|abc efg |123"; echo $vari |sed -e "s/$vari/$varj/g" This worked which suggests problem is with '&' – girish chalke Sep 29 '15 at 8:44

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