2

I have a data file of numbers seperated by tabs, like this

1 2 3 4
2 4 6 8

My real file is 50000 columns wide and I only need every 100th column (column 100, 200, 300, 400, ...). Now I would like to remove all the other columns.

How can I do that?

2

That's what awk is for:

awk '{for(i=100;i<=NF;i+=100){printf "%s ",$i;} print ""}' file > output

Or, if you can have spaces inside your fields, specify tab as the field separator:

awk -F'\t' '{for(i=100;i<=NF;i+=100){printf "%s ",$i;} print ""}' file > output

Alternatively, you could use Perl:

perl -ane 'for($i=99;$i<=$#F;$i+=100){print "$F[$i] "}' file > output

To do this for multiple files, you can use a shell loop (assuming you want to run this on all files in the current directory):

for f in *; do
  awk '{for(i=100;i<=NF;i+=100){printf "%s ",$i;} print ""}' "$f" > "$f".new;
done
  • I tried the first solution and it worked. Is there a way to automate this if I want to cut the columns from multiple files, which are called xy_1.txt, xy_2.txt, xy_3.txt, ...? – Blub Bla Sep 16 '15 at 14:02
  • @BlubBla see update. – terdon Sep 16 '15 at 14:05
0

Although I don't know if it's appropriated with big files, you can do this with cut:

cut -d " " -f -100 < [your file]
  • This will only print field 100, not every 100th field as the OP requested. – terdon Sep 16 '15 at 14:06
  • No it won't, unless you forget the dash before 100. – pedroapero Sep 16 '15 at 14:59
  • Ah, yes, my bad. This will print fields 1 to 100 though. Still not what the OP wants. – terdon Sep 16 '15 at 15:01
  • With cut you could use cut -d' ' -f$(seq -s, 0 100 N) where N is the total number of columns but as you said, this won't work with big numbers (you'll most likely get an argument list too long). – don_crissti Sep 16 '15 at 16:18
  • I just realize what "every 100th column" means. Indeed, the awk method is the one, especially with the NR operator. Cheers! – pedroapero Sep 16 '15 at 16:51

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